Physics 106 Homework2

Physics 106 Homework2 - Physics 106 Homework #2 Submitting...

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Physics 106 Homework #2 Submitting Answers Remember to be careful about units. Implicit multiplication is not understood. Type 3*x, not 3x Defined Constants The following constants can be used by name throughout this assignment: ke = 8.99×10 9 Nm 2 /C 2 qe = 1.6×10 –19 C mp = 1.67×10 –27 kg me = 9.11×10 –31 kg eps0 = 8.85×10 –12 C 2 /(Nm 2 ) g = 9.80 m/s 2 . Problem 2.1 Purpose: To calculate the electric field of a series of point charges. Problem with data for try #1 : Consider the picture to the right. The charge of the middle charge is 2.49 μC. Determine the electric field strength at a point 1.00 cm to the left of the middle charge. Additional input values q2 (C): 2.23, 2.62 Defined symbols: q2 charge of the middle charge in μC q1 charge of the left chargein μC q3 charge of the right charge in μC d12 distance between q1 and q2 in m d23 distance between q2 and q3 in m The answer is E electric field strength at a point 1.00 cm to the left of the middle charge in N/C Hints: You will have to calculate the electric field of each of the three charges at the point 1.00 cm left of the middle charge and add the results together. You add the electric field just like you added the forces in problem 4. It can be helpful to invent a small positively charged ball and place it at the point where you wish to find the field. The only thing that's different between finding the force on this ball and the electric field at this point is that the electric field doesn't include the charge of the ball. Range of answers: –1.15×10 8 N/C to +2.00×10 7 N/C . Problem 2.2
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Purpose: This is a continuation of Problem 1. The input values are the same as for Problem 1. Problem with data for try #1 : Consider the picture below. The charge of the middle charge is 2.49 μC. If a charge of +2.00 μC is placed at a point 1.00 cm to the left of the middle charge, what are the magnitude and direction of the force on it? (Let a force to the right be positive and a force to the left be negative.) Additional input values q2 (C): 2.23, 2.62 Defined symbols: q charge of the test charge in μC q2 charge of the middle charge in μC q1 charge of the left chargein μC q3 charge of the right charge in μC d12 distance between q1 and q2 in m d23 distance between q2 and q3 in m The answer is F1 magnitude of the force on the +2.00 μC charge in N Hints: Since we know the electric field from the previous problem (Be sure to use the E from the correct input!), the force is just F=qE . Because you know the electric field strength at that point, you can recalculate the force on any charge placed there without having to add all the vectors again. Range of answers –230 N to +40.0 N . Problem 2.3
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This document was uploaded on 12/15/2011.

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Physics 106 Homework2 - Physics 106 Homework #2 Submitting...

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