1_ch 05 Mechanical Design budynas_SM_ch05

1_ch 05 Mechanical Design budynas_SM_ch05 -...

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Chapter 5 5-1 MSS: σ 1 σ 3 = S y / n n = S y σ 1 σ 3 DE: n = S y σ ± σ ± = ( σ 2 A σ A σ B + σ 2 B ) 1 / 2 = ( σ 2 x σ x σ y + σ 2 y + 3 τ 2 xy ) 1 / 2 (a) MSS: σ 1 = 12, σ 2 = 6, σ 3 = 0 kpsi n = 50 12 = 4 . 17 Ans. DE: σ ± = (12 2 6(12) + 6 2 ) 1 / 2 = 10 . 39 kpsi, n = 50 10 . 39 = 4 . 81 Ans. (b) σ A , σ B = 12 2 ² ± ² 12 2 ³ 2 + ( 8) 2 = 16, 4 kpsi σ 1 = 16, σ 2 = 0, σ 3 =− 4 kpsi MSS: n = 50 16 ( 4) = 2 . 5 Ans. DE: σ ± = (12 2 + 3( 8 2 )) 1 / 2 = 18 . 33 kpsi, n = 50 18 . 33 = 2 . 73 Ans. (c) σ A , σ B = 6 10 2 ² ± ² 6 + 10 2 ³ 2 + ( 5) 2 =− 2 . 615, 13 . 385 kpsi σ 1 = 0, σ 2 =− 2 . 615, σ 3 =− 13 . 385 kpsi MSS: n = 50 0 ( 13 . 385) = 3 . 74 Ans. DE: σ ± = [( 6) 2 ( 6)( 10) + ( 10) 2 + 3( 5) 2 ] 1 / 2 = 12 . 29 kpsi n = 50 12 . 29 = 4 . 07 Ans.
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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