2_ch 13 Mechanical Design budynas_SM_ch13

# 2_ch 13 Mechanical Design budynas_SM_ch13 - p x = p t tan...

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334 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 13-5 (a) A O = " µ 2 . 333 2 2 + µ 5 . 333 2 2 # 1 / 2 = 2 . 910 in Ans. (b) γ = tan 1 (14 / 32) = 23 . 63° Ans. 0 = tan 1 (32 / 14) = 66 . 37° Ans. (c) d P = 14 / 6 = 2 . 333 in, d G = 32 / 6 = 5 . 333 in Ans. (d) From Table 13-3, 0 . 3 A O = 0 . 873 in and 10 / P = 10 / 6 = 1 . 67 0 . 873 < 1 . 67 F = 0 . 873 in Ans. 13-6 (a) p n = π/ 5 = 0 . 6283 in p t = p n / cos ψ = 0 . 6283 / cos 30° = 0 . 7255 in
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Unformatted text preview: p x = p t / tan ψ = . 7255 / tan 30° = 1 . 25 in 30 8 P G 2 1 3 " 5 1 3 " A O G g 10.5 8 Arc of approach 5 0.87 in Ans. Arc of recess 5 0.77 in Ans. Arc of action 5 1.64 in Ans. L ab 5 1.53 in 10 8 O 2 O 1 14 8 12.6 8 P B A...
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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