2_ch 20 Mechanical Design budynas_SM_ch20

2_ch 20 Mechanical Design budynas_SM_ch20 -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
2 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 20-2 Data represents a 7-class histogram with N = 197. 20-3 Form a table: ¯ x = 4548 58 = 78 . 4 kpsi s x = ± 359 088 4548 2 / 58 58 1 ² 1 / 2 = 6 . 57 kpsi From Eq. (20-14) f ( x ) = 1 6 . 57 2 π exp ³ 1 2 ´ x 78 . 4 6 . 57 µ 2 xf f x fx 2 64 2 128 8192 68 6 408 27 744 72 6 432 31 104 76 9 684 51 984 80 19 1520 121 600 84 10 840 70 560 88 4 352 30 976 92 2 184 16 928 58 4548 359 088
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

Ask a homework question - tutors are online