3_ch 03 Mechanical Design budynas_SM_ch03

3_ch 03 Mechanical Design budynas_SM_ch03 -...

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16 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Step 2: Find components of R C on link 4 and R D ± + ± M C = 0 400(4 . 5) (7 . 794 1 . 9) R D = 0 R D = 305 . 4N Ans. ± F x = 0 ( R Cx ) 4 = 305 . ± F y = 0 ( R Cy ) 4 =− 400 N Step 3: Find components of R C on link 2 ± F x = 0 ( R ) 2 + 305 . 4 346 . 4 = 0 ( R ) 2 = 41 N ± F y = 0 ( R ) 2 = 200 N 3-3 (a) ± + ± M 0 = 0 18(60) + 14 R 2 + 8(30) 4(40) = 0 R 2 = 71 . 43 lbf ± F y = 0: R 1 40 + 30 + 71 . 43 60 = 0 R 1 1 . 43 lbf M 1 1 . 43(4) 5 . 72 lbf · in M 2 5 . 72 41 . 43(4) 171 . 44 lbf · in M 3 171 . 44 11 . 43(6) 240 lbf · in M 4 240 + 60(4) = 0 checks! 4" 4" 6" 4" ± 1.43 ± 41.43 ± 11.43 60 40 lbf 60 lbf 30 lbf x x
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