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3_ch 04 Mechanical Design budynas_SM_ch04

# 3_ch 04 Mechanical Design budynas_SM_ch04 - 6 C 1 dy dx = 0...

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72 Solutions Manual Instructor’s Solution Manual to Accompany Mechanical Engineering Design Then k = F δ = π Er 1 ( r 1 + l tan α ) l = E A 1 l 1 + 2 l d 1 tan α Ans. 4-6 F = ( T + dT ) + w dx T = 0 dT dx = − w Solution is T = − w x + c T | x = 0 = P + w l = c T = − w x + P + w l T = P + w ( l x ) The infinitesmal stretch of the free body of original length dx is d δ = Tdx AE = P + w ( l x ) AE dx Integrating, δ = l 0 [ P + w ( l x )] dx AE δ = Pl AE + w l 2 2 AE Ans. 4-7 M = w lx w l 2 2 w x 2 2 E I dy dx = w lx 2 2 w l 2 2 x w x
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Unformatted text preview: 6 + C 1 , dy dx = 0 at x = 0, ± C 1 = E I y = w lx 3 6 − w l 2 x 2 4 − w x 4 24 + C 2 , y = 0 at x = 0, ± C 2 = y = w x 2 24 E I (4 lx − 6 l 2 − x 2 ) Ans. l x dx P Enlarged free body of length dx w is cable’s weight per foot T ± dT w dx T...
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