3_ch 14 Mechanical Design budynas_SM_ch14

3_ch 14 Mechanical Design budynas_SM_ch14 -...

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Chapter 14 351 14-7 d = 24 5 = 4 . 8in , Y = 0 . 337 V = π (4 . 8)(50) 12 = 62 . 83 ft/min Eq. (14-4 b ): K v = 1200 + 62 . 83 1200 = 1 . 052 W t = 63 025 H nd / 2 = 63 025(6) 50(4 . 8 / 2) = 3151 lbf Eq. (14-7): F = K v W t P σ Y = 1 . 052(3151)(5) 20(10 3 )(0 . 337) = 2 . 46 in Use F = 2 . 5in Ans. 14-8 d = 16 5 = 3 . 2in , Y = 0 . 296 V = π (3 . 2)(600) 12 = 502 . 7 ft/min Eq. (14-4 b ): K v = 1200 + 502 . 7 1200 = 1 . 419 W t = 63 025(15) 600(3 . 2 / 2) = 984 . 8 lbf Eq. (14-7): F = K v W t P σ Y = 1 . 419(984 . 8)(5) 10(10 3 )(0 . 296) = 2 . 38 in Use F = 2 . 5in Ans. 14-9 Try P = 8 which gives d = 18 / 8
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