3_ch 17 Mechanical Design budynas_SM_ch17

3_ch 17 Mechanical Design budynas_SM_ch17 -...

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422 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Ex. 17-2: b = 10 in, d = 16 in, D = 32 in, Polyamide A-3, t = 0 . 13 in, γ = 0 . 042, F a = 100 lbf/in, C p = 0 . 94, C v = 1, f = 0 . 8 T = 63 025(60)(1 . 15)(1 . 05) 860 = 5313 lbf · in w = 12 γ bt = 12(0 . 042)(10)(0 . 13) = 0 . 655 lbf/ft V = π dn / 12 = π (16)(860 / 12) = 3602 ft/min θ d = 3 . 037 rad For fully-developed friction: exp( f θ d ) = [0 . 8(3 . 037)] = 11 . 35 F c = w V 2 g = 0 . 655(3602 / 60) 2 32 . 174 = 73 . 4 lbf ( F 1 ) a = F 1 = bF a C p C v = 10(100)(0 . 94)(1) = 940 lbf ± F = 2 T / D = 2(5313) / (16) = 664 lbf F 2 = F 1 ± F = 940 664 = 276 lbf F i = F 1 + F 2 2 F c = 940 + 276 2 73 . 4 = 535 lbf Transmitted power H (or H a ): H = ± F ( V ) 33 000 = 664(3602) 33 000 = 72 . 5hp f ± = 1 θ d ln ± F 1 F c F 2 F c ² = 1 3 . 037 ln ± 940 73 . 4 276 73 . 4 ² = 0 . 479 undeveloped Note, in this as well as in the double-size case, exp( f θ d ) is not used. It will show up if we
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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