4_ch 01 Mechanical Design budynas_SM_ch01

4_ch 01 Mechanical Design budynas_SM_ch01 - σ = 42(10 3...

This preview shows page 1. Sign up to view the full content.

4 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 1-9 (a) σ = 20(6.89) = 137.8 MPa (b) F = 350(4.45) = 1558 N = 1.558 kN (c) M = 1200 lbf · in (0.113) = 135.6 N · m (d) A = 2 . 4(645) = 1548 mm 2 (e) I = 17 . 4in 4 (2 . 54) 4 = 724 . 2cm 4 (f) A = 3 . 6(1 . 610) 2 = 9 . 332 km 2 (g) E = 21(1000)(6 . 89) = 144 . 69(10 3 )MPa = 144 . 7GPa (h) v = 45 mi/h (1.61) = 72.45 km/h (i) V = 60 in 3 (2 . 54) 3 = 983 . 2cm 3 = 0 . 983 liter 1-10 (a) l = 1.5 / 0.305 = 4.918 ft = 59.02 in (b) σ = 600 / 6.89 = 86.96 kpsi (c) p = 160 / 6.89 = 23.22 psi (d) Z = 1 . 84(10 5 ) / (25 . 4) 3 = 11 . 23 in 3 (e) w = 38.1 / 175 = 0.218 lbf/in (f) δ = 0.05 / 25.4 = 0.00197 in (g) v = 6.12 / 0.0051 = 1200 ft/min (h) ² = 0.0021 in/in (i) V = 30 / (0 . 254) 3 = 1831 in 3 1-11 (a) σ = 200 15 . 3 = 13 . 1MPa (b)
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: σ = 42(10 3 ) 6(10 − 2 ) 2 = 70(10 6 ) N/m 2 = 70 MPa (c) y = 1200(800) 3 (10 − 3 ) 3 3(207)10 9 (64)10 3 (10 − 3 ) 4 = 1 . 546(10 − 2 ) m = 15 . 5 mm (d) θ = 1100(250)(10 − 3 ) 79 . 3(10 9 )( π/ 32)(25) 4 (10 − 3 ) 4 = 9 . 043(10 − 2 ) rad = 5 . 18 ◦ 1-12 (a) σ = 600 20(6) = 5 MPa (b) I = 1 12 8(24) 3 = 9216 mm 4 (c) I = π 64 32 4 (10 − 1 ) 4 = 5 . 147 cm 4 (d) τ = 16(16) π (25 3 )(10 − 3 ) 3 = 5 . 215(10 6 ) N/m 2 = 5.215 MPa...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online