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6_ch 17 Mechanical Design budynas_SM_ch17

# 6_ch 17 Mechanical Design budynas_SM_ch17 -...

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Chapter 17 425 (b) See Prob. 17-4 statement. The final relation can be written b min = 1 F a C p C v (12 γ t / 32 . 174)( V / 60) 2 33 000 H a exp( f θ ) V [exp( f θ ) 1] = 1 100(0 . 7)(1) −{ [12(0 . 042)(0 . 13)] / 32 . 174 } (2749 / 60) 2 33 000(20 . 6)(11 . 17) 2749(11 . 17 1) = 4 . 13 in Ans . This is the minimum belt width since the belt is at the point of slip. The design must round up to an available width. Eq. (17-1): θ d = π 2 sin 1 D d 2 C = π 2 sin 1 18 6 2(96) = 3 . 016 511 rad θ D = π + 2 sin 1 D d 2 C = π + 2 sin 1 18 6 2(96) = 3 . 266 674 Eq. (17-2): L = [4(96) 2 (18 6) 2 ] 1 / 2 + 1 2 [18(3 . 266 674) + 6(3 . 016 511)] = 230 . 074 in Ans
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