7_ch 13 Mechanical Design budynas_SM_ch13

# 7_ch 13 Mechanical Design budynas_SM_ch13 -...

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Chapter 13 339 13-16 e = 6 10 µ 18 38 ¶µ 20 48 ¶µ 3 36 = 3 304 n a = 3 304 (1200) = 11 . 84 rev/min cw Ans . 13-17 (a) n c = 12 40 · 1 1 (540) = 162 rev/min cw about x . Ans . (b) d P = 12 / (8 cos 23°) = 1 . 630 in d G = 40 / (8 cos 23°) = 5 . 432 in d P + d G 2 = 3 . 531 in Ans . (c) d = 32 4 = 8inat the large end of the teeth. Ans . 13-18 (a) The planet gears act as keys and the wheel speeds are the same as that of the ring gear. Thus n A = n 3 = 1200(17 / 54) = 377 . 8rev/min Ans . (b) n F = n 5 = 0, n L = n 6 , e =− 1 1 = n 6 377 . 8 0 377 . 8 377 . 8 = n 6 377 . 8 n 6 = 755 . 6rev/min Ans . Alternatively, the velocity of the center of gear 4 is v 4 c N 6 n 3 . The velocity of the left edge of gear 4 is zero since the left wheel is resting on the ground. Thus, the ve- locity of the right edge of gear 4 is 2 v 4 c 2 N 6 n 3 . This velocity, divided by the radius of gear 6 N 6 , is angular velocity of gear 6–the speed of wheel 6. n 6 = 2 N 6 n 3 N 6 = 2 n 3 = 2(377 . 8) = 755 . 6rev/min Ans
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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