8_ch 04 Mechanical Design budynas_SM_ch04

8_ch 04 Mechanical Design budynas_SM_ch04 -...

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Chapter 4 77 4-18 I = π d 4 / 64 = π( 2 ) 4 / 64 = 0 . 7854 in 4 Tables A-9-5 and A-9-9 y =− F 2 l 3 48 EI + F 1 a 24 EI (4 a 2 3 l 2 ) =− 120(40) 3 48(30)(10 6 )(0 . 7854) + 85(10)(400 4800) 24(30)(10 6 )(0 . 7854) =− 0 . 0134 in Ans. 4-19 (a) Useful relations k = F y = 48 EI l 3 I = kl 3 48 E = 2400(48) 3 48(30)10 6 = 0 . 1843 in 4 From I = bh 3 / 12 h = 3 ± 12(0 . 1843) b Form a table. First, Table A-17 gives likely available fractional sizes for b : 8 1 2 , 9 , 9 1 2 , 10 in For h : 1 2 , 9 16 , 5 8 , 11 16 , 3 4 For available b what is necessary h for required
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