8_ch 06 Mechanical Design budynas_SM_ch06

8_ch 06 Mechanical Design budynas_SM_ch06 - = 178 . 4 MPa...

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154 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 6-13 Yield: σ ± max = [69 2 + 3(138) 2 ] 1 / 2 = 248 . 8MPa n y = S y σ ± max = 413 248 . 8 = 1 . 66 Ans . σ ± a = 69 MPa, σ ± m = 3(138) = 239 MPa (a) Modified Goodman, Table 6-6 n f = 1 (69 / 276) + (239 / 551) = 1 . 46 Ans . (b) Gerber, Table 6-7 n f = 1 2 ± 551 239 ² 2 ± 69 276 ² 1 + ³ 1 + ´ 2(239)(276) 551(69) µ 2 = 1 . 73 Ans . (c) ASME-Elliptic, Table 6-8 n f = ´ 1 (69 / 276) 2 + (239 / 413) 2 µ 1 / 2 = 1 . 59 Ans . 6-14 Yield: σ ± max = [83 2 + 3(103 + 69) 2 ] 1 / 2 = 309 . 2MPa n y = S y σ ± max = 413 309 . 3 = 1 . 34 Ans . σ ± a = σ 2 a + 3 τ 2 a = · 83 2 + 3(69 2 ) = 145 . 5MPa, σ ± m = 3(103)
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Unformatted text preview: = 178 . 4 MPa (a) Modied Goodman, Table 6-6 n f = 1 (145 . 5 / 276) + (178 . 4 / 551) = 1 . 18 Ans . (b) Gerber, Table 6-7 n f = 1 2 551 178 . 4 2 145 . 5 276 1 + 1 + 2(178 . 4)(276) 551(145 . 5) 2 = 1 . 47 Ans . (c) ASME-Elliptic, Table 6-8 n f = 1 (145 . 5 / 276) 2 + (178 . 4 / 413) 2 1 / 2 = 1 . 47 Ans ....
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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