8_ch 12 Mechanical Design budynas_SM_ch12

# 8_ch 12 Mechanical Design budynas_SM_ch12 - For the same b...

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Chapter 12 311 If this is c min , b d = 2(0 . 001) = 0 . 002 in The median clearance is ¯ c = c min + t d + t b 2 = 0 . 001 + t d + t b 2 and the clearance range for this bearing is ± c = t d + t b 2 which is a function only of the tolerances. For maximum W : r c = ± 0 . 2 0 . 185(10 6 ) = 1040 c = 0 . 625 / 1040 = 0 . 000 600 . = 0 . 0005 in If this is c min b d ± = 2 c min = 2(0 . 0005) = 0 . 001 in ¯ c = c min + t d + t b 2 = 0 . 0005 + t d + t b 2 ± c = t d + t b 2 The difference (mean) in clearance between the two clearance ranges, c range , is c range = 0 . 001 + t d + t b 2 ² 0 . 0005 + t d + t b 2 ³ = 0 . 0005 in For the minimum f bearing b d = 0 . 002 in or d = b 0 . 002 in For the maximum W bearing d ± = b 0 . 001 in
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Unformatted text preview: For the same b , t b and t d , we need to change the journal diameter by 0.001 in. d ± − d = b − . 001 − ( b − . 002) = . 001 in Increasing d of the minimum friction bearing by 0.001 in, deﬁnes d ± of the maximum load bearing. Thus, the clearance range provides for bearing dimensions which are attainable in manufacturing. Ans....
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