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8_ch 16 Mechanical Design budynas_SM_ch16

# 8_ch 16 Mechanical Design budynas_SM_ch16 -...

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Chapter 16 403 16-9 (a) Counter-clockwise rotation, θ 2 = π/ 4 rad, r = 13 . 5 / 2 = 6 . 75 in a = 4 r sin θ 2 2 θ 2 + sin 2 θ 2 = 4(6 . 75) sin( π/ 4) 2 π/ 4 + sin(2 π/ 4) = 7 . 426 in e = 2(7 . 426) = 14 . 85 in Ans. (b) α = tan 1 (3 / 14 . 85) = 11 . M R = 0 = 3 F x 6 . 375 P F x = 2 . 125 P F x = 0 = − F x + R x R x = F x = 2 . 125 P F y = F x tan 11 . 4 = 0 . 428 P F y = − P F y + R y R y = P + 0 . 428 P = 1 . 428 P Left shoe lever. M R = 0 = 7 . 78 S x 15 . 28 F x S x = 15 . 28 7 . 78 (2 . 125 P ) = 4 . 174 P S y = f S x = 0 . 30(4 . 174 P ) = 1 . 252 P F y = 0 = R y + S y + F y R y = − F y S y = − 0 . 428 P 1 . 252 P = − 1 . 68 P F x = 0 = R x S x + F x R x = S x F x
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