Chapter 1742717-7Find the resultant of F1and F2:α=sin−1D−d2Csinα=D−d2Ccosα˙=1−12±D−d2C²2Rx=F1cosα+F2cosα=(F1+F2)³1−12±D−d2C²2´Ans.Ry=F1sinα−F2sinα=(F1−F2)D−d2CAns.From Ex. 17-2, d=16 in, D=36 in, C=16(12)=192 in, F1=940 lbf, F2=276 lbfα=sin−1µ36−162(192)¶=2.9855◦Rx=(940+276)³1−12±36−162(192)²2´=1214.4 lbfRy=(940−276)µ36−162(192)¶=34.6 lbfT=(F1−F2)±d2²=(940−276)±162²=5312 lbf·in17-8Begin with Eq. (17-10),F1=Fc+Fi2exp(
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.