8_ch 17 Mechanical Design budynas_SM_ch17

8_ch 17 Mechanical Design budynas_SM_ch17 -...

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Chapter 17 427 17-7 Find the resultant of F 1 and F 2 : α = sin 1 D d 2 C sin α = D d 2 C cos α ˙= 1 1 2 ± D d 2 C ² 2 R x = F 1 cos α + F 2 cos α = ( F 1 + F 2 ) ³ 1 1 2 ± D d 2 C ² 2 ´ Ans . R y = F 1 sin α F 2 sin α = ( F 1 F 2 ) D d 2 C Ans . From Ex. 17-2, d = 16 in, D = 36 in, C = 16(12) = 192 in, F 1 = 940 lbf, F 2 = 276 lbf α = sin 1 µ 36 16 2(192) = 2 . 9855 R x = (940 + 276) ³ 1 1 2 ± 36 16 2(192) ² 2 ´ = 1214 . 4 lbf R y = (940 276) µ 36 16 2(192) = 34 . 6 lbf T = ( F 1 F 2 ) ± d 2 ² = (940 276) ± 16 2 ² = 5312 lbf · in 17-8 Begin with Eq. (17-10), F 1 = F c + F i 2exp(
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