8_ch 20 Mechanical Design budynas_SM_ch20

8_ch 20 Mechanical Design budynas_SM_ch20 -...

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8 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 20-10 E = ± ( y a 0 a 2 x 2 ) 2 E a 0 =− 2 ± ( y a 0 a 2 x 2 ) = 0 ± y na 0 a 2 ± x 2 = 0 ± y = 0 + a 2 ± x 2 E a 2 = 2 ± ( y a 0 a 2 x 2 ) (2 x ) = 0 ± xy = a 0 ± x + a 2 ± x 3 Ans. Cramer’s rule a 0 = ² ² ² ² ± y ± x 2 ± ± x 3 ² ² ² ² ² ² ² n ± x 2 ± x ± x 3 ² ² ² = ± x 3 ± y ± x 2 ± n ± x 3 ± x ± x 2 a 2 = ² ² ² n ± y ± x ± ² ² ² ² ² ² n ± x 2 ± x ± x 3 ² ² ² = n ± ± x ± y n ± x 3 ± x ± x 2 a 0 = 800 000(56) 12 000(2400) 4(800 000) 200(12 000) = 20 a 2 = 4(2400) 200(56) 4(800 000)
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