9_ch 08 Mechanical Design budynas_SM_ch08

# 9_ch 08 Mechanical Design budynas_SM_ch08 - 20 mm, E = 25...

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212 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Eq. (8-23): k m = 207(12)(0 . 787 15) exp[(0 . 628 73)(12 / 40)] = 2361 MN/m k s = 2 k m = 4722 MN/m Cast iron: A = 0 . 778 71, B = 0 . 616 16, E = 100 GPa k m = 100(12)(0 . 778 71) exp[(0 . 616 16)(12 / 40)] = 1124 MN/m k ci = 2 k m = 2248 MN/m 1 k m = 1 k s + 1 k ci k m = 1523 MN/m C = 466 . 8 466 . 8 + 1523 = 0 . 2346 Table 8-1: A t = 84 . 3mm 2 , Table 8-11, S p = 600 MPa Eqs. (8-30) and (8-31): F i = 0 . 75(84 . 3)(600)(10 3 ) = 37 . 9kN Eq. (8-28): n = S p A t F i CP = 600(10 3 )(84 . 3) 37 . 9 0 . 2346(10 . 6) = 5 . 1 Ans . 8-21 Computer programs will vary. 8-22 D 3 = 150 mm, A = 100 mm, B = 200 mm, C = 300 mm, D =
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Unformatted text preview: 20 mm, E = 25 mm. ISO 8.8 bolts: d = 12 mm, p = 1 . 75 mm, coarse pitch of p = 6 MPa. P = 1 10 ± π 4 ² (150 2 )(6)(10 − 3 ) = 10 . 6 kN/bolt l = D + E = 20 + 25 = 45 mm L T = 2 D + 6 = 2(12) + 6 = 30 mm Table A-31: H = 10 . 8 mm l + H = 45 + 10 . 8 = 55 . 8 mm Table A-17: L = 60 mm l d = 60 − 30 = 30 mm, l t = 45 − 30 = 15 mm, A d = π (12 2 / 4) = 113 mm 2 Table 8-1: A t = 84 . 3 mm 2 2.5 d w D 1 22.5 25 45 20...
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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