9_ch 12 Mechanical Design budynas_SM_ch12

9_ch 12 Mechanical Design budynas_SM_ch12 - T = 2(68C 60C)...

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312 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 12-11 Given: SAE 30, N = 8rev/s, T s = 60°C, l / d = 1, d = 80 mm, b = 80 . 08 mm, W = 3000 N c min = b min d max 2 = 80 . 08 80 2 = 0 . 04 mm r = d / 2 = 80 / 2 = 40 mm r c = 40 0 . 04 = 1000 P = 3000 80(80) = 0 . 469 MPa Trial #1 : From Figure 12-13 for T = 81°C, µ = 12 mPa · s ± T = 2(81°C 60°C) = 42°C S = (1000 2 ) ± 12(10 3 )(8) 0 . 469(10 6 ) ² = 0 . 2047 From Fig. 12-24, 0 . 120 ± T P = 0 . 349 + 6 . 009(0 . 2047) + 0 . 0475(0 . 2047) 2 = 1 . 58 ± T = 1 . 58 ³ 0 . 469 0 . 120 ´ = 6 . 2°C Discrepancy = 42°C 6 . 2°C = 35 . 8°C Trial #2 : From Figure 12-13 for T = 68°C, µ = 20 mPa · s,
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Unformatted text preview: T = 2(68C 60C) = 16C S = . 2047 20 12 = . 341 From Fig. 12-24, . 120 T P = . 349 + 6 . 009(0 . 341) + . 0475(0 . 341) 2 = 2 . 4 T = 2 . 4 . 469 . 120 = 9 . 4C Discrepancy = 16C 9 . 4C = 6 . 6C Trial #3 : = 21 mPa s, T = 65C T = 2(65C 60C) = 10C S = . 2047 21 12 = . 358...
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