9_ch 15 Mechanical Design budynas_SM_ch15

9_ch 15 Mechanical Design budynas_SM_ch15 -...

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Chapter 15 387 15-9 Pinion core ( s at ) P = 44(300) + 2100 = 15 300 psi ( σ all ) P = 15 300(0 . 862) 1(1)(1 . 25) = 10 551 psi W t = 10 551(1 . 25)(0 . 249) 6(1)(1 . 374)(0 . 5222)(1 . 106) = 689 . 7 lbf Gear core ( s at ) G = 44(352) + 2100 = 17 588 psi ( σ all ) G = 17 588(0 . 893) 1(1)(1 . 25) = 12 565 psi W t = 12 565(1 . 25)(0 . 216) 6(1)(1 . 374)(0 . 5222)(1 . 106) = 712 . 5 lbf Pinion case ( s ac ) P = 341(372) + 23 620 = 150 472 psi ( σ c ,all ) P = 150 472(1) 1(1)(1 . 118) = 134 590 psi W t = ± 134 590 2290 ² 2 ³ 1 . 25(3 . 333)(0 . 086) 1(1 . 374)(1 . 106)(0 . 593 75)(2) ´ = 685 . 8 lbf Gear case ( s ac ) G = 341(344) + 23 620 = 140 924 psi ( σ c ,all ) G = 140 924(1 . 0685)(1) 1(1)(1 . 118) = 134 685 psi W t = ± 134 685 2290 ² 2 ³ 1 . 25(3 . 333)(0 . 086) 1(1 . 374)(1 . 106)(0 . 593 75)(2) ´ =
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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