10_ch 03 Mechanical Design budynas_SM_ch03

# 10_ch 03 Mechanical Design budynas_SM_ch03 -...

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Unformatted text preview: budynas_SM_ch03.qxd 11/28/2006 21:21 FIRST PAGES Page 23 23 Chapter 3 4 1 −1 4 tan 2 3 φp = = 26.6◦ cw x 26.6 14 φs = 45◦ − 26.6◦ = 18.4◦ ccw τ1 = R = 5, 9 9 18.4 x 5 9 9 (b) y 9 + 16 = 12.5 2 16 − 9 CD = = 3.5 2 C= 1 cw (9, 5cw) R D C 2 2 R= 1 2 p σ1 = 6.1 + 12.5 = 18.6 5 1 φ p = tan−1 = 27.5◦ ccw 2 3.5 σ2 = 12.5 − 6.1 = 6.4 s (16, 5ccw) ccw 2 52 + 3.52 = 6.10 x 6.4 18.6 27.5 x τ1 = R = 6.10 , φs = 45◦ − 27.5◦ = 17.5◦ cw 12.5 6.10 x 17.5 12.5 (c) 1 cw y C= (24, 6cw) R D 1 2 (10, 6ccw) ccw 2 p 24 − 10 =7 2 R = 72 + 62 = 9.22 CD = C 2 24 + 10 = 17 2 σ1 = 17 + 9.22 = 26.22 σ2 = 17 − 9.22 = 7.78 s x 2 ...
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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