10_ch 05 Mechanical Design budynas_SM_ch05

# 10_ch 05 Mechanical Design budynas_SM_ch05 - 27 Ans(d σ x...

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124 Solutions Manual Instructor’s Solution Manual to Accompany Mechanical Engineering Design (a) σ x = 90 kpsi, σ y = − 50 kpsi, σ z = 0 σ A = 90 kpsi and σ B = − 50 kpsi. For the fourth quadrant, from Eq. (5-31b) n = 1 ( σ A / S yt ) ( σ B / S uc ) = 1 (90 / 235) ( 50 / 275) = 1 . 77 Ans. (b) σ x = 120 kpsi, τ xy = − 30 kpsi ccw. σ A , σ B = 127 . 1, 7 . 08 kpsi. For the fourth quadrant n = 1 (127 . 1 / 235) ( 7 . 08 / 275) = 1 . 76 Ans. (c) σ x = − 40 kpsi, σ y = − 90 kpsi, τ xy = 50 kpsi. σ A , σ B = − 9 . 10, 120 . 9 kpsi . Although no solution exists for the third quadrant, use n = − S yc σ y = − 275 120 . 9
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Unformatted text preview: . 27 Ans. (d) σ x = 110 kpsi, σ y = 40 kpsi, τ xy = 10 kpsi cw. σ A , σ B = 111 . 4, 38 . 6 kpsi. For the ﬁrst quadrant n = S yt σ A = 235 111 . 4 = 2 . 11 Ans. Graphical Solution: (a) n = OB O A = 1 . 82 1 . 02 = 1 . 78 (b) n = OD OC = 2 . 24 1 . 28 = 1 . 75 (c) n = OF OE = 2 . 75 1 . 24 = 2 . 22 (d) n = OH OG = 2 . 46 1 . 18 = 2 . 08 O ( d ) ( b ) ( a ) ( c ) E F B D G C A H 1 in ± 100 kpsi ± B ± A...
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