10_ch 08 Mechanical Design budynas_SM_ch08

# 10_ch 08 Mechanical Design budynas_SM_ch08 - t 1 = h = 20...

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Chapter 8 213 Eq. (8-17): k b = 113(84 . 3)(207) 113(15) + 84 . 3(30) = 466 . 8 MN/m There are three frusta: d m = 1 . 5(12) = 18 mm D 1 = (20 tan 30 )2 + d w = (20 tan 30 )2 + 18 = 41 . 09 mm Upper Frustum: t = 20 mm, E = 207 GPa, D = 1 . 5(12) = 18 mm Eq. (8-20): k 1 = 4470 MN/m Central Frustum: t = 2 . 5mm, D = 41 . 09 mm, E = 100 GPa (Table A-5) k 2 = 52 230 MN/m Lower Frustum: t = 22 . 5mm, E = 100 GPa, D = 18 mm k 3 = 2074 MN/m From Eq. (8-18): k m = [(1 / 4470) + (1 / 52 230) + (1 / 2074)] 1 = 1379 MN/m Eq. ( e ), p. 421: C = 466 . 8 466 . 8 + 1379 = 0 . 253 Eqs. (8-30) and (8-31): F i = KF p = KA t S p = 0 . 75(84 . 3)(600)(10 3 ) = 37 . 9kN Eq. (8-28): n = S p A t F i CP = 600(10 3 )(84 . 3) 37 . 9 0 . 253(10 . 6) = 4 . 73 Ans . 8-23 P = 1 8 ± π 4 ² (120 2 )(6)(10 3 ) = 8 . 48 kN From Fig. 8-21,
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Unformatted text preview: t 1 = h = 20 mm and t 2 = 25 mm l = 20 + 12 / 2 = 26 mm t = (no washer), L T = 2(12) + 6 = 30 mm L > h + 1 . 5 d = 20 + 1 . 5(12) = 38 mm Use 40 mm cap screws. l d = 40 − 30 = 10 mm l t = l − l d = 26 − 10 = 16 mm A d = 113 mm 2 , A t = 84 . 3 mm 2 Eq. (8-17): k b = 113(84 . 3)(207) 113(16) + 84 . 3(10) = 744 MN/m Ans . d w = 1 . 5(12) = 18 mm D = 18 + 2(6)(tan 30) = 24 . 9 mm l ± 26 t 2 ± 25 h ± 20 13 13 7 6 D 12...
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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