10_ch 09 Mechanical Design budynas_SM_ch09

# 10_ch 09 Mechanical Design budynas_SM_ch09 - 135 7 h in 4...

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248 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design presentation of the drawing to you. Here is one possibility. Study the problem’s opportuni- ties, then present this (or your sketch) with the problem assignment. Use b 1 as the design variable. Express properties as a function of b 1 . From Table 9-3, category 3: A = 1 . 414 h ( b b 1 ) ¯ x = b / 2, ¯ y = d / 2 I u = bd 2 2 b 1 d 2 2 = ( b b 1 ) d 2 2 I = 0 . 707 hI u τ ± = V A = F 1 . 414 h ( b b 1 ) τ ±± = Mc I = Fa ( d / 2 ) 0 . 707 hI u τ max = ± τ ± 2 + τ ±± 2 Parametric study Let a = 10 in, b = 8 in, d = 8 in, b 1 = 2in, τ all = 12 . 8 kpsi, l = 2(8 2) = 12 in A = 1 . 414 h (8 2) = 8 . 48 h in 2 I u = (8 2)(8 2 / 2) = 192 in 3 I = 0 . 707( h )(192) =
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Unformatted text preview: 135 . 7 h in 4 τ ± = 10 000 8 . 48 h = 1179 h psi τ ±± = 10 000(10)(8 / 2) 135 . 7 h = 2948 h psi τ max = 1 h ± 1179 2 + 2948 2 = 3175 h = 12 800 from which h = . 248 in . Do not round off the leg size – something to learn. fom ± = I u hl = 192 . 248(12) = 64 . 5 A = 8 . 48(0 . 248) = 2 . 10 in 2 I = 135 . 7(0 . 248) = 33 . 65 in 4 Section AA A 36 Body welds not shown 8" 8" 1 2 " a A A 10000 lbf 1018 HR Attachment weld pattern considered b b 1 d...
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