{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

10_ch 13 Mechanical Design budynas_SM_ch13

# 10_ch 13 Mechanical Design budynas_SM_ch13 - 2 N 2 N 3 N 5...

This preview shows page 1. Sign up to view the full content.

342 Solutions Manual Instructor’s Solution Manual to Accompany Mechanical Engineering Design 13-25 n 2 = n b = n F , n A = n a , n L = n 5 = 0 e = − 21 444 = n L n A n F n A 21 444 ( n F n A ) = 0 n A With shaft b as input 21 444 n F + 21 444 n A + 444 444 n A = 0 n A n F = n a n b = 21 465 n a = 21 465 n b , in the same direction as shaft b , the input. Ans . Alternatively, v A N 4 = n 2 N 2 N 3 + N 4 v A = n 2 N 2 N 4 N 3 + N 4 n a = n A = v A N 2 + N 3 = n 2 N 2 N 4 ( N 2 + N 3 )( N 3 + N 4 ) = 18(21)( n b ) (18 + 72)(72 + 21) = 21 465 n b in the same direction as b Ans . 13-26 n F = n 2 = n a , n L = n 6 = 0 e = − 24 18 22 64 = − 11 24 , e = n L n A n F n A = 0 n b n a n b 11 24 = 0 n b n a n b n b n a = 11 35 Ans . Yes, both shafts rotate in the same direction. Ans. Alternatively, v A
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 N 2 N 3 + N 5 = N 2 N 3 + N 5 n a , v A = N 2 N 5 N 3 + N 5 n a n A = n b = v A N 2 + N 3 = N 2 N 5 ( N 2 + N 3 )( N 3 + N 5 ) n a n b n a = 24(22) (24 + 18)(22 + 18) = 11 35 Ans . n b rotates ccw ∴ Yes Ans . 13-27 n 2 = n F = 0, n L = n 5 = n b , n A = n a e = + 20 24 µ 20 24 ¶ = 25 36 3 5 v 5 v A n 2 N 2 2 3 4 2 v 5 v A n 2 N 2...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern