11_ch 05 Mechanical Design budynas_SM_ch05

11_ch 05 Mechanical Design budynas_SM_ch05 - . For the...

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Chapter 5 125 5-11 The material is brittle and exhibits unequal tensile and compressive strengths. Decision: Use the Modified Mohr theory. S ut = 22 kpsi, S uc = 83 kpsi (a) σ x = 9 kpsi, σ y =− 5 kpsi. σ A , σ B = 9, 5 kpsi. For the fourth quadrant, | σ B σ A |= 5 9 < 1, use Eq. (5-32 a ) n = S ut σ A = 22 9 = 2 . 44 Ans. (b) σ x = 12 kpsi, τ xy =− 3 kpsi ccw. σ A , σ B = 12 . 7, 0 . 708 kpsi. For the fourth quad- rant, | σ B σ A |= 0 . 708 12 . 7 < 1, n = S ut σ A = 22 12 . 7 = 1 . 73 Ans. (c) σ x =− 4 kpsi, σ y =− 9 kpsi, τ xy = 5 kpsi. σ A , σ B =− 0 . 910, 12 . 09 kpsi
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Unformatted text preview: . For the third quadrant, no solution exists; however, use Eq. (6-32 c ) n = − 83 − 12 . 09 = 6 . 87 Ans. (d) σ x = 11kpsi, σ y = 4kpsi, τ xy = 1kpsi. σ A , σ B = 11 . 14, 3 . 86 kpsi. Forthefirstquadrant n = S A σ A = S yt σ A = 22 11 . 14 = 1 . 97 Ans. 30 30 S ut ± 22 S ut ± 83 ± B ± A –50 –90 ( d ) ( b ) ( a ) ( c )...
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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