11_ch 13 Mechanical Design budynas_SM_ch13

# 11_ch 13 Mechanical Design budynas_SM_ch13 - 42 5 = 9 36 kN...

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Chapter 13 343 25 36 = n b n a 0 n a n b n a = 11 36 Ans. Same sense, therefore shaft b rotates in the same direction as a . Ans. Alternatively, v 5 N 3 N 4 = ( N 2 + N 3 ) n a N 3 v 5 = ( N 2 + N 3 )( N 3 N 4 ) n N 3 n b = v 5 N 5 = ( N 2 + N 3 )( N 3 N 4 ) n a N 3 N 5 n b n a = (20 + 24)(24 20) 24(24) = 11 36 same sense Ans. 13-28 (a) ω = 2 π n / 60 H = T ω = 2 π Tn / 60 ( T in N · m, H in W) So T = 60 H (10 3 ) 2 π n = 9550 H / n ( H in kW, n in rev/min) T a = 9550(75) 1800 = 398 N · m r 2 = mN 2 2 = 5(17) 2 = 42 . 5mm So F t 32 = T a r 2 = 398
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Unformatted text preview: 42 . 5 = 9 . 36 kN F 3 b = − F b 3 = 2(9 . 36) = 18 . 73 kN in the positive x-direction. Ans. See the Fgure in part (b) on the following page. 9.36 2 a T a 2 398 N•m F t 32 3 4 v 5 v 5 ( N 2 1 N 3 ) n a...
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