12_ch 03 Mechanical Design budynas_SM_ch03

12_ch 03 Mechanical Design budynas_SM_ch03 -...

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Chapter 3 25 3-9 (a) C = 12 4 2 = 4 CD = 12 + 4 2 = 8 R = 8 2 + 7 2 = 10 . 63 σ 1 = 4 + 10 . 63 = 14 . 63 σ 2 = 4 10 . 63 = − 6 . 63 φ p = 1 2 90 + tan 1 8 7 = 69 . 4 ccw τ 1 = R = 10 . 63, φ s = 69 . 4 45 = 24 . 4 ccw (b) C = 6 5 2 = 0 . 5 CD = 6 + 5 2 = 5 . 5 R = 5 . 5 2 + 8 2 = 9 . 71 σ 1 = 0 . 5 + 9 . 71 = 10 . 21 σ 2 = 0 . 5 9 . 71 = − 9 . 21 φ p = 1 2 tan 1 8 5 . 5 = 27 . 75 ccw x 10.21 9.21 27.75 2 s ( 5, 8 cw ) C R D 2 1 1 2 2 p (6, 8 ccw
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