13_ch 09 Mechanical Design budynas_SM_ch09

13_ch 09 Mechanical Design budynas_SM_ch09 -...

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Chapter 9 251 τ ±± = Mc I = 10 000(10)(8 / 2) 135 . 7 h = 2948 h psi τ max = ± τ ± 2 + τ ±± 2 = 1 h (1179 2 + 2948 2 ) 1 / 2 = 3175 h psi Equate the maximum and allowable shear stresses. τ max = τ all = 3175 h = 12 800 from which h = 0 . 248 in . It follows that I = 135 . 7(0 . 248) = 33 . 65 in 4 The volume of the weld metal is vol = h 2 l 2 = 0 . 248 2 (6 + 6) 2 = 0 . 369 in 3 The effectiveness, (eff) H ,is (eff) H = I vol = 33 . 65 0 . 369 = 91 . 2in (fom ± ) H = I u hl = 192 0 . 248(6 + 6) = 64 . 5in Vertical parallel weld beads b = 6in d = 8in From Table 9-2, category 2 A = 1 . 414 hd = 1 . 414( h )(8) = 11 . 31 h in 2 ¯
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