14_ch 07 Mechanical Design budynas_SM_ch07

# 14_ch 07 Mechanical Design budynas_SM_ch07 -...

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Chapter 7 191 At x = 11 in: θ = 1449(9)(11 2 9 2 ) 6(30)(10 6 )( π/ 64)(1 . 875 4 )(11) = 4 . 342(10 4 ) rad Obtain allowable slopes from Table 7-2. Left bearing : n fs = Allowable slope Actual slope = 0 . 001 0 . 000 282 3 = 3 . 54 Right bearing : n fs = 0 . 0008 0 . 000 434 2 = 1 . 84 Gear mesh slope : Table 7-2 recommends a minimum relative slope of 0.0005 rad. While we don’t know the slope on the next shaft, we know that it will need to have a larger diameter and be stiffer. At the moment we can say n fs < 0 . 0005 0 . 000 304 = 1 . 64 7-9 The solution to Problem 7-8 may be used as an example of the analysis process for a similar situation. 7-10 If you have a ﬁnite element program available, it is highly recommended. Beam deﬂection programs can be implemented but this is time consuming and the programs have narrow ap- plications. Here we will demonstrate how the problem can be simpliﬁed and solved using
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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