14_ch 16 Mechanical Design budynas_SM_ch16

14_ch 16 Mechanical Design budynas_SM_ch16 -...

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Chapter 16 409 Eq. (16-24): T = π fp a d 8 ( D 2 d 2 ) N = π (0 . 24)(120)(4) 8 (6 . 5 2 4 2 )(6) = 7125 lbf · in Ans . (b) T = π (0 . 24)(120 d ) 8 (6 . 5 2 d 2 )(6) d ,in T , lbf · in 2 5191 3 6769 4 7125 Ans. 5 5853 6 2545 (c) The torque-diameter curve exhibits a stationary point maximum in the range of diameter d . The clutch has nearly optimal proportions. 16-18 (a) T = π fp a d ( D 2 d 2 ) N 8 = CD 2 d Cd 3 Differentiating with respect to d and equating to zero gives dT dd = CD 2 3 Cd 2 = 0 d * = D 3 Ans. d 2 T dd 2 =− 6 Cd
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