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15_ch 03 Mechanical Design budynas_SM_ch03

# 15_ch 03 Mechanical Design budynas_SM_ch03 -...

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28 Solutions Manual Instructor’s Solution Manual to Accompany Mechanical Engineering Design (b) C = 30 10 2 = 10 CD = 30 + 10 2 = 20 R = 20 2 + 10 2 = 22 . 36 σ 1 = 10 + 22 . 36 = 32 . 36 σ 2 = 10 22 . 36 = − 12 . 36 φ p = 1 2 tan 1 10 20 = 13 . 28 ccw τ 1 = R = 22 . 36, φ s = 45 13 . 28 = 31 . 72 cw (c) C = 10 + 18 2 = 4 CD = 10 + 18 2 = 14 R = 14 2 + 9 2 = 16 . 64 σ 1 = 4 + 16 . 64 = 20 . 64 σ 2 = 4 16 . 64 = − 12 . 64 φ p = 1 2 90 + tan 1 14 9 = 73 . 63 cw τ 1 = R = 16 . 64, φ s = 73 . 63 45 = 28

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15_ch 03 Mechanical Design budynas_SM_ch03 -...

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