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15_ch 12 Mechanical Design budynas_SM_ch12

# 15_ch 12 Mechanical Design budynas_SM_ch12 - Â s S = 055 Â³...

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318 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Trial #1 : Choose ( T f ) 1 = 79°C . From Fig. 12-13, µ = 13 mPa · s . S = (595 2 ) ± 13(10 3 )(48) 4000(10 3 ) ² = 0 . 055 From Figs. 12-18 and 12-16: fr c = 2 . 3, ± = 0 . 85 . From Eq. (12-25), ² T = 978(10 6 ) 1 + 1 . 5 ± 2 ( fr / c ) SW 2 p s r 4 = 978(10 6 ) 1 + 1 . 5(0 . 85) 2 ± 2 . 3(0 . 055)(10 2 ) 200(25) 4 ² = 76 . 0°C T a v = T s + ² T / 2 = 55°C + (76°C / 2) = 93°C Trial #2 : Choose ( T f ) 2 = 100°C. From Fig. 12-13, µ = 7mPa · s . S = 0 . 055 ³ 7 13 ´ = 0 . 0296 From Figs. 12-18 and 12-16: fr c = 1 . 6, ± = 0 . 90 ² T = 978(10 6 ) 1 + 1 . 5(0 . 9) 2 ± 1 . 6(0 . 0296)(10 2 ) 200(25) 4 ² = 26 . 8°C T a v = 55°C + 26 . 8°C 2 = 68 . 4°C Trial #3 : Thus, the plot gives ( T f ) 3 = 85°C . From Fig. 12-13, µ = 10 . 8mPa
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Unformatted text preview: Â· s . S = . 055 Â³ 10 . 8 13 Â´ = . 0457 From Figs. 12-18 and 12-16: f r c = 2 . 2, Â± = . 875 Â² T = 978(10 6 ) 1 + 1 . 5(0 . 875 2 ) Â± 2 . 2(0 . 0457)(10 2 ) 200(25) 4 Â² = 58 . 6Â°C T a v = 55Â°C + 58 . 6Â°C 2 = 84 . 3Â°C Result is close. Choose Â¯ T f = 85Â°C + 84 . 3Â°C 2 = 84 . 7Â°C 100 T av T f 60 70 80 90 100 (79 Â± C, 93 Â± C) (79 Â± C, 79 Â± C) 85 Â± C (100 Â± C, 68.4 Â± C) (100 Â± C, 100 Â± C) 90 80 70 T av Â² T f...
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