15_ch 13 Mechanical Design budynas_SM_ch13

# 15_ch 13 Mechanical Design budynas_SM_ch13 - F r = 4202...

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Chapter 13 347 Gear 3 W t 23 = W t 32 = 622 lbf W r 23 = W r 32 = 226 lbf F b 3 = F b 2 = 662 lbf R C = R D = 662 / 2 = 331 lbf Each bearing on shaft b has the same radial load which is equal to the radial load of bear- ings, A and B. Thus, all four bearings have the same radial load of 331 lbf. Ans . 13-32 Given: P = 4 teeth/in, φ n = 20 , N P = 20 T , n 2 = 900 rev/min. d 2 = N P P = 20 4 = 5 . 000 in T in = 63 025(30)(2) 900 = 4202 lbf · in W t 32 = T in / ( d 2 / 2) = 4202 / (5 / 2) = 1681 lbf W r 32 = 1681 tan 20 = 612 lbf The motor mount resists the equivalent forces and torque. The radial force due to torque
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Unformatted text preview: F r = 4202 14(2) = 150 lbf Forces reverse with rotational sense as torque reverses. C D A B 150 14" 150 150 4202 lbf•in 150 y 2 612 lbf 4202 lbf•in 1681 lbf z Equivalent y z 2 W t 32 5 1681 lbf W r 32 5 612 lbf Load on 2 due to 3 3 2 y x y z 3 T out 5 W t 23 r 3 5 2799 lbf•in b F b t 3 W t 23 W r 23 F b r 3...
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