17_ch 08 Mechanical Design budynas_SM_ch08

17_ch 08 Mechanical Design budynas_SM_ch08 - 2 l = D + E =...

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220 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design (b) Gerber Eq. (8-42) S a = 1 2 S e ± S ut ² S 2 ut + 4 S e ( S e + σ i ) S 2 ut 2 σ i S e ³ = 1 2(129) ´ 830 µ 830 2 + 4(129)(129 + 450) 830 2 2(450)(129) = 76 . 99 MPa n f = 76 . 99 14 . 75 = 5 . 22 Ans . (c) ASME-elliptic Eq. (8-43) with S p = 600 MPa S a = S e S 2 p + S 2 e · S p ² S 2 p + S 2 e σ 2 i σ i S e ¸ = 129 600 2 + 129 2 ´ 600 µ 600 2 + 129 2 450 2 450(129) = 65 . 87 MPa n f = 65 . 87 14 . 75 = 4 . 47 Ans . 8-32 P = pA N = π D 2 p 4 N = π (0 . 9 2 )(550) 4(36) = 9 . 72 kN/bolt Table 8-11: S p = 830 MPa, S ut = 1040 MPa, S y = 940 MPa Table 8-1: A t = 58 mm 2 A d = π (10 2 ) / 4 = 78 . 5mm
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Unformatted text preview: 2 l = D + E = 20 + 25 = 45 mm L T = 2(10) + 6 = 26 mm Table A-31: H = 8 . 4 mm L ≥ l + H = 45 + 8 . 4 = 53 . 4 mm Choose L = 60 mm from Table A-17 l d = L − L T = 60 − 26 = 34 mm l t = l − l d = 45 − 34 = 11 mm k b = A d A t E A d l t + A t l d = 78 . 5(58)(207) 78 . 5(11) + 58(34) = 332 . 4 MN/m 2.5 22.5 22.5 25 20 15 10...
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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