17_ch 13 Mechanical Design budynas_SM_ch13

17_ch 13 Mechanical Design budynas_SM_ch13 -...

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Chapter 13 349 The shear forces are independent of the rotational sense. The bolt tensions and the shear forces for cw rotation are, Tension (lbf) Shear (lbf) A0 145 B0 145 C1 109 300 D1 109 300 For ccw rotation, Tension (lbf) Shear (lbf) A 182 145 B 182 145 C0 300 D0 300 13-33 T in = 63 025 H / n = 63 025(2 . 5) / 240 = 656 . 5 lbf · in W t = T / r = 656 . 5 / 2 = 328 . 3 lbf γ = tan 1 (2 / 4) = 26 . 565° 0 = tan 1 (4 / 2) = 63 . 435° a = 2 + (1 . 5 cos 26 . 565°) / 2 = 2 . 67 in W r = 328 . 3 tan 20° cos 26 . 565° = 106 . 9 lbf W a = 328 . 3 tan 20° sin 26 . 565° = 53 . 4 lbf W = 106 . 9 i 53 . 4 j + 328 . 3 k lbf R AG =− 2 i + 5 . 17 j , R AB = 2 . 5 j ± M 4 = R × W + R × F B + T = 0 Solving gives R ×
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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