{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

17_ch 13 Mechanical Design budynas_SM_ch13

17_ch 13 Mechanical Design budynas_SM_ch13 -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 13 349 The shear forces are independent of the rotational sense. The bolt tensions and the shear forces for cw rotation are, Tension (lbf) Shear (lbf) A 0 145 B 0 145 C 1109 300 D 1109 300 For ccw rotation, Tension (lbf) Shear (lbf) A 182 145 B 182 145 C 0 300 D 0 300 13-33 T in = 63 025 H / n = 63 025(2 . 5) / 240 = 656 . 5 lbf · in W t = T / r = 656 . 5 / 2 = 328 . 3 lbf γ = tan 1 (2 / 4) = 26 . 565° = tan 1 (4 / 2) = 63 . 435° a = 2 + (1 . 5 cos 26 . 565°) / 2 = 2 . 67 in W r = 328 . 3 tan 20° cos 26 . 565° = 106 . 9 lbf W a = 328 . 3 tan 20° sin 26 . 565° = 53 . 4 lbf W = 106 . 9 i 53 . 4 j + 328 . 3 k lbf R AG = − 2 i + 5 . 17 j , R AB = 2 . 5 j M 4 = R AG × W + R AB × F B + T = 0 Solving gives R AB × F
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}