18_ch 03 Mechanical Design budynas_SM_ch03

18_ch 03 Mechanical Design budynas_SM_ch03 -...

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Chapter 3 31 (b) C = 30 60 2 = − 15 CD = 60 + 30 2 = 45 R = 45 2 + 30 2 = 54 . 1 σ 1 = − 15 + 54 . 1 = 39 . 1 σ 2 = 0 σ 3 = − 15 54 . 1 = − 69 . 1 τ 1 / 3 = 39 . 1 + 69 . 1 2 = 54 . 1, τ 1 / 2 = 39 . 1 2 = 19 . 6, τ 2 / 3 = 69 . 1 2 = 34 . 6 (c) C = 40 + 0 2 = 20 CD = 40 0 2 = 20 R = 20 2 + 20 2 = 28 . 3 σ 1 = 20 + 28 . 3 = 48 . 3 σ 2 = 20 28 . 3 = − 8 . 3 σ 3 = σ z = − 30 τ 1 / 3 = 48 . 3 + 30 2 = 39 . 1, τ 1 / 2 = 28 . 3, τ 2 / 3 = 30 8 . 3 2 = 10 . 9 (d) C = 50 2 = 25 CD = 50 2 = 25 R = 25 2 + 30 2 = 39 . 1 σ 1 = 25 + 39 . 1 = 64 . 1 σ 2 = 25 39 . 1 = − 14 . 1 σ 3 = σ z = − 20 τ 1 / 3 = 64 . 1 + 20 2 = 42 . 1, τ 1 / 2 = 39 . 1, τ 2 / 3 = 20 14 . 1 2 = 2 . 95 1 (50, 30
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