92Solutions Manual• Instructor’s Solution Manual to Accompany Mechanical Engineering Design4-45Place a dummy load Qat the center. Then,M=wx2(l−x)+Qx2U=2±l/20M2dx2EI,ymax=∂U∂Q²²²²Q=0ymax=2³±l/202M2´∂M∂Qµ¶Q=0ymax=2·±l/20³wx2(l−x)+2¶x2¾Q=0Set Q=0 and integrateymax=w2´lx33−x44µl/20ymax=5wl4384Ans.4-46I=2(1.85)=3.7in4Adding weight of channels of 0.833 lbf·in,M=−Fx−10.8332x2−5.417x2∂M∂FxδB=1±480M∂M∂F=1±480(+5.417x2)(x)=(220/3)(483)+(5.417/4)(484)30(106)(3.7)=0.1378 inin direction of 220 lbf± yB0.1378 in
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.