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23_ch 08 Mechanical Design budynas_SM_ch08

# 23_ch 08 Mechanical Design budynas_SM_ch08 - P = 9 96 149(2...

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226 Solutions Manual Instructor’s Solution Manual to Accompany Mechanical Engineering Design Coarse thread, UNC F i = 0 . 75(0 . 969)(74) = 53 . 78 kip σ i = F i A t = 53 . 78 0 . 969 = 55 . 5 kpsi σ a = C P 2 A t = 0 . 30 P 2(0 . 969) = 0 . 155 P kpsi Eq. (8-42): S a = 1 2(16 . 3) 105 105 2 + 4(16 . 3)(16 . 3 + 55 . 5) 105 2 2(55 . 5)(16 . 3) = 9 . 96 kpsi n f = S a σ a = 9 . 96 0 . 155 P = 2 From which P = 9 . 96 0 . 155(2) = 32 . 13 kip Ans . Fine thread, UNF F i = 0 . 75(1 . 073)(74) = 59 . 55 kip σ i = 59 . 55 1 . 073 = 55 . 5 kpsi σ a = 0 . 32 P 2(1 . 073) = 0 . 149 P kpsi S a = 9 . 96 (as before) n f = S a σ a = 9 . 96 0 . 149 P = 2 From which
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Unformatted text preview: P = 9 . 96 . 149(2) = 33 . 42 kip Ans . Percent improvement 33 . 42 − 32 . 13 32 . 13 (100) . = 4% Ans . 8-37 For a M 30 × 3 . 5 ISO 8 . 8 bolt with P = 80 kN/bolt and C = . 33 Table 8-1: A t = 561 mm 2 Table 8-11: S p = 600 MPa S ut = 830 MPa Table 8-17: S e = 129 MPa...
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