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23_ch 20 Mechanical Design budynas_SM_ch20

23_ch 20 Mechanical Design budynas_SM_ch20 - 90 1 2 66 = 78...

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Chapter 20 23 n (kcycles) f W ( n ) f LN ( n ) 40 9.1E-05 1.82E-05 50 0.000991 0.000241 60 0.002498 0.001233 70 0.004380 0.003501 80 0.006401 0.006739 90 0.008301 0.009913 100 0.009822 0.012022 110 0.010750 0.012644 120 0.010965 0.011947 130 0.010459 0.010399 140 0.009346 0.008492 150 0.007827 0.006597 160 0.006139 0.004926 170 0.004507 0.003564 180 0.003092 0.002515 190 0.001979 0.001739 200 0.001180 0.001184 210 0.000654 0.000795 220 0.000336 0.000529 The Weibull L10 life comes from Eq. (20-26) with a reliability of R = 0 . 90 . Thus, n 0 . 10 = 36 . 9 + (133 36 . 9)[ln(1
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Unformatted text preview: / . 90)] 1 / 2 . 66 = 78 . 1 kcycles Ans. The lognormal L10 life comes from the definition of the z variable. That is, ln n = µ y + ˆ σ y z or n = exp( µ y + ˆ σ y z ) From Table A-10, for R = . 90, z = − 1 . 282 . Thus, n = exp[4 . 771 + . 2778( − 1 . 282)] = 82 . 7 kcycles Ans. f ( n ) n , kcycles 0.004 0.002 0.006 0.008 0.010 0.012 0.014 100 50 150 200 LN W 250...
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