24_ch 14 Mechanical Design budynas_SM_ch14

24_ch 14 Mechanical Design budynas_SM_ch14 -...

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Unformatted text preview: budynas_SM_ch14.qxd 372 14-26 12/05/2006 17:39 Page 372 FIRST PAGES Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Solution summary from Prob. 14-24: n = 1145 rev/min, K o = 1.25, Grade 1 materials, N P = 22T , NG = 60T , m G = 2.727, Y P = 0.331, YG = 0.422, J P = 0.345, JG = 0.410, Pd = 4T /in, F = 3.25 in, Q v = 6, ( Nc ) P = 3(109 ), R = 0.99 Pinion H B : 250 core, 390 case Gear H B : 250 core, 390 case K m = 1.240, K T = 1, K B = 1, d P = 5.500 in, dG = 15.000 in, V = 1649 ft/min, K v = 1.534, ( K s ) P = ( K s ) G = 1, ( Y N ) P = 0.832, ( Y N ) G = 0.859, K R = 1 Bending ( σall ) P = 26 728 psi ( St ) P = 32 125 psi ( σall ) G = 27 546 psi ( St ) G = 32 125 psi t W1 = 3151 lbf, H1 = 157.5 hp t W2 = 3861 lbf, H2 = 192.9 hp Wear φ = 20◦ , ( Z N ) G = 0.769, I = 0.1176, ( Z N ) P = 0.727, C P = 2300 psi ( Sc ) P = Sc = 322(390) + 29 100 = 154 680 psi ( σc, all ) P = 154 680(0.727) = 112 450 psi 1(1)(1) ( σc, all ) G = 154 680(0.769) = 118 950 psi 1(1)(1) 2 t W3 = 112 450 79 679 t W4 = 118 950 109 600(0.769) (1061) = 2113 lbf, H3 = 2113(1649) = 105.6 hp 33 000 H4 = 2354(1649) = 117.6 hp 33 000 2 (1182) = 2354 lbf, Rated power Hrated = min(157.5, 192.9, 105.6, 117.6) = 105.6 hp Prob. 14-24 Ans . Hrated = min(157.5, 192.9, 53.0, 59.0) = 53 hp The rated power approximately doubled. 14-27 The gear and the pinion are 9310 grade 1, carburized and case-hardened to obtain Brinell 285 core and Brinell 580–600 case. Table 14-3: 0.99 ( St ) 107 = 55 000 psi ...
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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