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24_ch 14 Mechanical Design budynas_SM_ch14

# 24_ch 14 Mechanical Design budynas_SM_ch14 -...

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14-26 Solution summary from Prob. 14-24: n = 1145 rev/min, K o = 1 . 25, Grade 1 materials, N P = 22 T , N G = 60 T , m G = 2 . 727 , Y P = 0 . 331 , Y G = 0 . 422, J P = 0 . 345, J G = 0 . 410, P d = 4 T /in, F = 3 . 25 in , Q v = 6, ( N c ) P = 3(10 9 ), R = 0 . 99 Pinion H B : 250 core, 390 case Gear H B : 250 core, 390 case K m = 1 . 240, K T = 1, K B = 1, d P = 5 . 500 in, d G = 15 . 000 in, V = 1649 ft/min, K v = 1 . 534, ( K s ) P = ( K s ) G = 1, ( Y N ) P = 0 . 832, ( Y N ) G = 0 . 859, K R = 1 Bending ( σ all ) P = 26 728 psi ( S t ) P = 32 125 psi ( σ all ) G = 27 546 psi ( S t ) G = 32 125 psi W t 1 = 3151 lbf, H 1 = 157 . 5 hp W t 2 = 3861 lbf, H 2 = 192 . 9 hp Wear φ = 20 , I = 0 . 1176 , ( Z N ) P = 0 . 727, ( Z N ) G = 0 . 769, C P = 2300 psi ( S c ) P = S c = 322(390) + 29 100 = 154 680 psi ( σ c , all ) P = 154 680(0 . 727) 1(1)(1) = 112 450 psi ( σ c , all ) G = 154 680(0 . 769) 1(1)(1) = 118 950 psi W t 3 = 112 450 79 679 2 (1061) = 2113 lbf, H 3 = 2113(1649) 33 000 = 105 . 6 hp W t 4 = 118 950 109 600(0 . 769) 2 (1182) = 2354 lbf, H 4 = 2354(1649) 33 000 = 117 . 6 hp Rated power H rated
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