25_ch 06 Mechanical Design budynas_SM_ch06

25_ch 06 Mechanical Design budynas_SM_ch06 -...

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Chapter 6 171 Decision: Depending on availability, (1) select t = 10 mm, recalculate n f and R , and determine whether the reduced reliability is acceptable, or, (2) select t = 11 mm or larger, and determine whether the increase in cost and weight is acceptable. Ans . 6-34 Rotation is presumed. M and S ut are given as deterministic, but notice that σ is not; there- fore, a reliability estimation can be made. From Eq. (6-70): S ± e = 0 . 506(110) LN (1, 0 . 138) = 55 . 7 LN . 138) kpsi Table 6-10: k a = 2 . 67(110) 0 . 265 LN . 058) = 0 . 768 LN . 058) Based on d = 1 in, Eq. (6-20) gives k b = ± 1 0 . 30 ² 0 . 107 = 0 . 879 Conservatism is not necessary S e = 0 . 768[ LN . 058)](0 . 879)(55 . 7)[ LN . 138)] ¯ S e = 37 . 6 kpsi C Se = (0 . 058 2 + 0 . 138 2 ) 1 / 2 = 0 . 150 S e = 37 . 6 LN .
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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