26_ch 07 Mechanical Design budynas_SM_ch07

26_ch 07 Mechanical Design budynas_SM_ch07 -...

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Chapter 7 203 For the hub: Eq. (7-45): σ t ,hub = p d 2 o + d 2 d 2 o d 2 = (14 720) ± 2 . 5 2 + 1 . 5 2 2 . 5 2 1 . 5 2 ² = 31 280 psi Eq. (7-46): σ r ,hub =− p =− 14 720 psi Eq. (5-13): σ ± = ( σ 2 1 σ 1 σ 2 + σ 2 2 ) 1 / 2 = [(31 280) 2 (31280)( 14 720) + ( 14 720) 2 ] 1 / 2 = 40 689 psi
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