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26_ch 13 Mechanical Design budynas_SM_ch13

# 26_ch 13 Mechanical Design budynas_SM_ch13 - 5 ◦(cos 7 59...

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358 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Radial F r D = 1566 j + 1669 k N Or F r D = 2289 N (total radial) F t D =− 637 i N (thrust) 13-43 V W = π (1 . 5)(900) 12 = 353 . 4 ft/min W x = W Wt = 33 000(0 . 5) 353 . 4 = 46 . 69 lbf p t = p x = π 10 = 0 . 314 16 in L = 0 . 314 16(2) = 0 . 628 in λ = tan 1 0 . 628 π (1 . 5) = 7 . 59° W = 46 . 7 cos 14 . 5° sin 7 . 59° + 0 . 05 cos 7 . 59° = 263 lbf W y = 263 sin 14 . 5 = 65 . 8 lbf W z = 263[cos 14
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Unformatted text preview: . 5 ◦ (cos 7 . 59 ◦ ) − . 05 sin 7 . 59 ◦ ] = 251 lbf So W = 46 . 7 i + 65 . 8 j + 251 k lbf Ans . T = 46 . 7(0 . 75) = 35 lbf · in Ans . 13-44 100:101 Mesh d P = 100 48 = 2 . 083 33 in d G = 101 48 = 2 . 104 17 in x y z W Wt G 0.75" T y z...
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