26_ch 14 Mechanical Design budynas_SM_ch14

26_ch 14 Mechanical Design budynas_SM_ch14 -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: budynas_SM_ch14.qxd 12/05/2006 17:39 Page 374 FIRST PAGES 374 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 14-29 n = 1145 rev/min, K o = 1.25, N P = 22T , NG = 60T , m G = 2.727, d P = 2.75 in, dG = 7.5 in, Y P = 0.331, YG = 0.422, J P = 0.335, JG = 0.405 , P = 8T /in, F = 1.625 in, H B = 250, case and core, both gears. Cm = 1, F /d P = 0.0591, C pm = 1, Cma = 0.152, Ce = 1, K m = 1.1942, K T = 1, C f = 0.0419, K β = 1, K s = 1, V = 824 ft/min, ( Y N ) P = 0.8318, ( Y N ) G = 0.859, K R = 1, I = 0.117 58 0.99 ( St ) 107 = 32 125 psi ( σall ) P = 26 668 psi ( σall ) G = 27 546 psi and it follows that t W1 = 879.3 lbf, H1 = 21.97 hp W2 = 1098 lbf, H2 = 27.4 hp t W3 = 304 lbf, H3 = 7.59 hp t W4 = 340 lbf, H4 = 8.50 hp t For wear Rating Hrated = min(21.97, 27.4, 7.59, 8.50) = 7.59 hp In Prob. 14-24, Hrated = 53 hp Thus 7.59 1 1 = 0.1432 = , not Ans . 53.0 6.98 8 The transmitted load rating is t Wrated = min(879.3, 1098, 304, 340) = 304 lbf In Prob. 14-24 t Wrated = 1061 lbf Thus 304 1 = 0.2865 = , 1061 3.49 14-30 S P = S H = 1, Bending Table 14-4: Pd = 4, 0.99 ( St ) 107 J P = 0.345, 1 not , 4 JG = 0.410, Ans . K o = 1.25 = 13 000 psi 13 000(1) = 13 000 psi 1(1)(1) σall F J P 13 000(3.25)(0.345) t W1 = = = 1533 lbf K o K v K s Pd K m K B 1.25(1.534)(1)(4)(1.24)(1) ( σall ) P = ( σall ) G = 1533(1649) = 76.6 hp 33 000 t t W2 = W1 JG / J P = 1533(0.410) /0.345 = 1822 lbf H2 = H1 JG / J P = 76.6(0.410) /0.345 = 91.0 hp H1 = ...
View Full Document

This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

Ask a homework question - tutors are online