28_ch 08 Mechanical Design budynas_SM_ch08

# 28_ch 08 Mechanical Design budynas_SM_ch08 -...

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Chapter 8 231 Bearing on bolt A b = 3 ± 3 8 ²± 5 16 ² = 0 . 3516 in 2 σ b =− F A b 5 . 4 0 . 3516 15 . 36 kpsi n S y σ b ± 92 15 . 36 ² = 5 . 99 Ans . Bearing on members A b = 0 . 3516 in 2 (From bearing on bolt calculations) σ b 15 . 36 kpsi (From bearing on bolt calculations) n S y σ b ± 57 15 . 36 ² = 3 . 71 Ans . Tension in members Failure across two bolts A = 5 16 ³ 2 3 8 2 ± 3 8 ²´ = 0 . 5078 in 2 σ = F A = 5 . 4 0 . 5078 = 10 . 63 kpsi n = S y σ t = 57 10 . 63 = 5 . 36 Ans. 8-44 By symmetry, R 1 = R 2 = 1 . 4kN µ M B = 01 . 4(250) 50 R A = 0 R A = 7kN µ M A = 0 200(1 . 4) 50 R B = 0 R B = 5 . 6kN Members:
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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