28_ch 10 Mechanical Design budynas_SM_ch10

28_ch 10 Mechanical Design budynas_SM_ch10 - 4 4 sin + 2 +...

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288 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design Upper 180 section: M = F [ R + R (1 cos φ )] = FR (2 cos φ ), M P = R (2 cos φ ) Lower section: M = FR sin θ M P = R sin θ Considering bending only: δ = 2 EI ±² L / 2 0 9 FR 2 dx + ² π 0 FR 2 (2 cos φ ) 2 Rd φ + ² π/ 2 0 F ( R sin θ ) 2 Rd θ ³ = 2 F EI ± 9 2 R 2 L + R 3 ´
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Unformatted text preview: 4 4 sin + 2 + R 3 4 = 2 F R 2 E I 19 4 R + 9 2 L = F R 2 2 E I (19 R + 18 L ) Ans. 10-35 Computer programs will vary. 10-36 Computer programs will vary. F R...
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