29_ch 05 Mechanical Design budynas_SM_ch05

29_ch 05 Mechanical Design budynas_SM_ch05 -...

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Chapter 5 143 (b) MSS: σ 1 σ 3 = S y σ 1 2 νσ 1 = S y ν = 1 3 σ 1 = 3 S y Ans. σ 3 = 2 3 σ 1 Radius of largest circle R = 1 2 ± σ 1 2 3 σ 1 ² = σ 1 6 5-42 (a) Ignoring stress concentration F = S y A = 160(4)(0 . 5) = 320 kips Ans. (b) From Fig. 6-36: h / b = 1, a / b = 0 . 625 / 4 = 0 . 1563, β = 1 . 3 Eq. (6-51) 70 = 1 . 3 F 4(0 . 5) ³ π (0 . 625) F = 76 . 9 kips Ans. 5-43 Given: a = 12 . 5mm , K Ic = 80 MPa · m , S y = 1200 MPa, S ut = 1350 MPa r o = 350 2 = 175 mm, r i = 350 50 2 = 150 mm a / ( r o r i ) = 12 . 5 175 150 = 0 . 5 r i / r o = 150 175 = 0 . 857
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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