29_ch 14 Mechanical Design budynas_SM_ch14

29_ch 14 Mechanical Design budynas_SM_ch14 - . 928) 1(0 ....

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Chapter 14 377 Table 14-6: S c = 180 000 psi ( Z N ) P = 2 . 466 ( 10 8 ) 0 . 056 = 0 . 8790 ( Z N ) G = 2 . 466 ( 10 8 / 3 . 059 ) 0 . 056 = 0 . 9358 ( σ c ,all ) P = 180 000(0 . 8790) 1(0 . 85) = 186 141 psi W t 3 = ± 186 141 2300 ² 2 ³ 1 . 963(1 . 5)(0 . 195) 1(1 . 404)(1 . 043) ´ = 2568 lbf H 3 = 2568(925) 33 000 = 72 . 0hp ( σ c ,all ) G = 0 . 9358 0 . 8790 (186 141) = 198 169 psi W t 4 = ± 198 169 186 141 ² 2 ± 1 . 043 1 . 052 ² (2568) = 2886 lbf H 4 = 2886(925) 33 000 = 80 . 9hp H rated = min(69 . 7, 91 . 3, 72, 80 . 9) = 69 . 7hp Ans . Pinion bending controlling 14-35 ( Y N ) P = 0 . 928, ( Y N ) G = 0 . 962 (See Prob. 14-34) Table 14-3: S t = 65 000 psi ( σ all ) P = 65 000(0
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Unformatted text preview: . 928) 1(0 . 85) = 70 965 psi W t 1 = 70 965(1 . 5)(0 . 423) 1(1 . 404)(1 . 043)(8 . 66)(1 . 208) = 2939 lbf H 1 = 2939(925) 33 000 = 82 . 4 hp ( σ all ) G = 65 000(0 . 962) 1(0 . 85) = 73 565 psi W t 2 = 73 565 70 965 ± . 5346 . 423 ² (2939) = 3850 lbf H 2 = 3850 2939 (82 . 4) = 108 hp...
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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