30_ch 03 Mechanical Design budynas_SM_ch03

30_ch 03 Mechanical Design budynas_SM_ch03 -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 3 43 F ( l + a ) + p 1 a 2 2 p 1 + p 2 6 a a 3 = 0 2 p 1 p 2 = 6 F ( l + a ) a 2 (2) From (1) and (2) p 1 = 2 F a 2 (3 l + 2 a ), p 2 = 2 F a 2 l + a ) (3) From similar triangles b p 2 = a p 1 + p 2 b = ap 2 p 1 + p 2 (4) M max occurs where V = 0 x max = l + a 2 b M max =− F ( l + a 2 b ) + p 1 2 ( a 2 b ) 2 p 1 + p 2 6 a ( a 2 b ) 3 Fl F ( a 2 b ) + p 1 2 ( a 2 b ) 2 p 1 + p 2 6 a ( a 2 b ) 3 Normally M max The fractional increase in the magnitude is ± = F ( a 2 b ) ( p 1 / 2)( a 2 b ) 2 [( p 1 + p 2 ) / 6 a ]( a 2 b ) 3 (5) For example, consider F = 1500 lbf, a = 1.2 in, l = 1.5 in (3) p 1 = 2(1500) 1 . 2 2 [3(1 . 5) + 2(1 . 2)] = 14 375 lbf/in
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online